SLAC Magnetic Measurements
Date: 07-12-1995
Time: 09:13:03

Magnet Name (Serial #): 089
Bar Code Number: 116
Project: PEP II High Energy Ring Sextupoles
Test Stand: IR8, S1
Measurement Coil: # 1
Operator: pdr
Run Number: 1
Comment: Standard Measurement

Standardization Currents (A):
   250.0    10.0   200.0    10.0   200.0    10.0   200.0
    10.0

Test Currents (A):
    25.0    50.0   100.0   125.0   150.0   175.0   200.0
   150.0   100.0    50.0    25.0



            INTEGRATED SEXTUPOLE STRENGTH VS CURRENT

Coil: Radius =  .044882  m, # Turns =  20 
Average: # Rotations/Measurement =  10 , # Measurements =  4 

  Imag    sigImag     SL     sigSL      SL/I   sigSL/I 
  (A)       (A)     (T/m)    (T/m)    (T/m/kA) (T/m/kA)
--------+--------  --------+--------  --------+--------
  25.640    0.002   3.66768  0.00090  143.0474   0.0365
  50.620    0.001   7.16787  0.00389  141.6018   0.0768
 100.608    0.001  14.32043  0.02210  142.3393   0.2197
 125.587    0.001  17.91935  0.00754  142.6846   0.0600
 150.591    0.004  21.55821  0.00744  143.1573   0.0496
 175.573    0.001  29.42336  0.54192  167.5851   3.0866
 200.587    0.003  31.99528  0.04018  159.5079   0.2003
 150.597    0.004  24.36652  0.04032  161.7995   0.2678
 100.617    0.003  16.28215  0.00445  161.8225   0.0445
  50.624    0.003   8.23027  0.00316  162.5773   0.0633
  25.637    0.001   4.22710  0.00231  164.8855   0.0905


           SUMMARY OF THE CALCULATIONS AND CONVENTIONS USED


Field Expansion:
The expansion of the radial and azimuthal field in polar
coordinates is
 Br(r,th) = Sum Bn (r/rref)^(n-1) cos(n(th-thspole))
 Bth(r,th) = -Sum Bn (r/rref)^(n-1) sin(n(th-thspole))
Our convention is to set rref = Rcoil.
Thspole is the angle of the first magnetic south pole
with respect to the horizontal, measured ccw by a shaft
encoder in the system.

Coil Voltage:
The coil voltage from each field harmonic is
 Vn(th) = Nturns * velocity * Brn(Rcoil,th) * L
L is the magnet effective length, or BLn is the integrated
field strength of the n'th harmonic.
At the coil radius, the radial field as a function of angle is,
 Brn(Rcoil,th) * L = BLn * cos(n*(th - thspole))
The coil voltage is
 Vn(th) = Nturns * velocity * BLn * cos(n*(th - thspole))
        = Nturns * Rcoil * ang_freq * BLn * cos(n*(th - THspole))
An FFT of the coil voltage gives Vn and PhiVn according to the formula
 Vn(i) = Vn * cos(n*2pi*i/N + PhiVn)

Multipole Field Calculations:
To find the multipole field magnitudes and phases,
the measured voltage harmonics are related to their values
calculated from the field harmonics:
 Nturns * Rcoil * ang_freq * BLn = Vn
 -n * thspole = PhiVn
Or,
 BLn = Vn / (Nturns * Rcoil * ang_freq)
 thspole = -PhiVn / n

Harmonic Strength Ratios:
The main field, denoted by capital N, is the field harmonic
with the largest strength at the coil radius.
The field strength ratio is defined by
 Rn = BLn / BLN
It gives the ratio of each harmonic field strength to the
main field strength at the coil radius.

Calculation Of SL:
The sextupole strength S is defined by the vertical
field on the x-axis (median plane).
It is the quadratic term in the Taylor expansion.
 By(x) = 1/2 S x^2
On the x-axis, By(x) = Bth(r=x,th=0)
From the expression for Bth above,
 By(x) = - B3 (x/rref)^2 sin(-3 thspole)
Take rref = Rcoil, thspole = pi/6, then at x=Rcoil,
 By(Rcoil) = B3 = 1/2 S Rcoil^2
So,
 S = 2 B3 / Rcoil^2
The integrated sextupole strength is
 SL = 2 BL3 / Rcoil^2

Calculation Of The Sextupole Center:
In the sextupole's frame,
 Bx' = S * x' * y'
 By' = 1/2 * S * (x'^2 - y'^2).
In the coil's frame (unprimed frame) the magnetic center is at (x0, y0).
In the coil's frame,
 Bx = S * (x - x0) * (y - y0)
 By = 1/2 * S * [(x - x0)^2 - (y - y0)^2].
The magnetic center can be found in terms of the measured
quadrupole field.  Compare Br and Btheta on the x-axis to
 Bxquad = -S * (x0 * y + y0 * x)
 Byquad = -S * (x0 * x - y0 * y).
Evaluate at x = Rcoil, y = 0 and compare to
 Br(theta = 0) = Bx, Btheta(theta = 0) = By.
In terms of the measured integrated strengths, this gives
 Xcenter = x0 = - (1/(SL * Rcoil)) * BL2 * sin(2 * THspole2)
 Ycenter = y0 = - (1/(SL * Rcoil)) * BL2 * cos(2 * THspole2)
